Calculate the freezing point of a solution containing 5.0 grams of KCl and 550.0 grams of water. The molal-freezing-point-depression constant () for water is 1.86

The freezing point of solution is -0.454°C

Explanation:

Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.

The equation used to calculate depression in freezing point follows:

To calculate the depression in freezing point, we use the equation:

Or,

where,

Freezing point of pure solution = 0°C

i = Vant hoff factor = 2

= molal freezing point elevation constant = 1.86°C/m

= Given mass of solute (KCl) = 5.0 g

= Molar mass of solute (KCl) = 74.55 g/mol

= Mass of solvent (water) = 550.0 g

Putting values in above equation, we get:

Hence, the freezing point of solution is -0.454°C

water is used to store them because it would keep the radiation from getting out in the open and causing harm to the workers

the formula for the conversion of temperature from degree celsius to kelvin is:

the sample of water at is converted to kelvin temperature by using the above formula as:

on comparing the two samples of water at or we can say that at and at respectively. the difference between the temperatures of two samples of water is:

hence, one can say that the sample of water at is greater than the sample of water at by .