In the following acid-base reactions, identify the spectator ions, if any:
(i) Cesium hydroxide(aq) + nitric acid(aq) =>
(ii) Calcium hydroxide(aq) + acetic acid(aq) =>
a.
(i) Cs+ and NO3-
(ii) no spectator ions
b.
(i) Cs+ and NO3-
(ii) H+ and OH-
c.
(i) no spectator ions
(ii) H+ and OH-
d.
(i) Cs+ and NO3-
(ii) Ca2+ and acetate ion.
e.
(i) no spectator ions
(ii) no spectator ions

Ineed someone to see if my answers are correct! if any are wrong let me know what the correct answers would be and how to get that answer! 1. how many moles of sodium chloride are in 28 grams od nacl? a. 265 mole naclb. 856 mole naclc. 479 mole of nacld. 1.2 mole nacl < my choice2. 734 grams of lithium sulfate (li2so4) are dissolved to make 2500 ml of solution what is rhe molaratiy? a. 2.67 mb. 4.56 mc. 3.89 m < my choiced. 1.78 m3. how many grams of cacl2 would be dissolved in 3.0 l of a 0.50 m solution of cacl2? a. 250 g cacl2 b. 166.5 g cacl2c. 113.65 g cacl2d. 98 g cacl2 < my choice4. suppose you had 58.44 g of nacl and you dissolved it in exactly 2.00 liters. the molarity if the solution would be 0.5 mtrue < my choicefalse 5. i would need 22g of naoh to make a 3.0 m solution using 250 ml of solvent. true < my choicefalse6. identify the solute: you have a .0195 m solution made from using 6.5 g of solute and 3 l of solvent. identify the solute by solving for molar weight. a. the solute is nacl because the molar weight is 58.43 g/mol < my choiceb. the solute is h2so4 because the molar weight is 98.06 g/molc. the solute is cacl2 because the molar weight is 111.11 g/mol

Define dew point. i am writing this part to be able to ask the question

Suppose you wanted to make 100 grams of water. what is the molar mass of water (h2o)?