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Chemistry, 07.03.2020 01:04, raenfall455
In the laboratory a student measures the percent ionization of a 0.498 M solution of acetylsalicylic acid (aspirin) , HC9H7O4, to be 2.53 %.
Calculate value of Ka from this experimental data.
Ka=
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Chemistry, 22.06.2019 16:00, julesperez22
Click the button that shows the correct relationship of the electron affinities of the elements sodium and phosphorus. sodium’s electron affinity value is more negative than the electron affinity value of phosphorus. phosphorus’ electron affinity value is more negative than the electron affinity value of sodium. this information cannot be determined using the periodic table. answer is b on e2020.
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In the laboratory a student measures the percent ionization of a 0.498 M solution of acetylsalicylic...
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