In the first 15.0 s of the reaction, 1.9×10−2 mol of O2 is produced in a reaction vessel with a volume of 0.480 L . What is the average rate of the reaction over this time interval?

The question is incomplete, here is the complete question:

Consider the following reaction:  

In the first 15.0 s of the reaction, 1.9×10⁻² mol of O₂ is produced in a reaction vessel with a volume of 0.480 L . What is the average rate of the reaction over this time interval?

The average rate of appearance of oxygen gas is

Explanation:

We are given:

Moles of oxygen gas =

Volume of solution = 0.480 L

Molarity is calculated by using the equation:

So,

The given chemical reaction follows:

The average rate of the reaction for appearance of is given as:

Or,

where,

= final concentration of oxygen gas = 0.0396 M

= initial concentration of oxygen gas = 0 M

= final time = 15.0 s

= initial time = 0 s

Putting values in above equation, we get:

Hence, the average rate of appearance of oxygen gas is

c, liquids evaporate, creating a gas

i think its 5049.

i hope this !