Cyclopropane thermally decomposes by a first‑order reaction to form propene. If the rate constant is 9.6 s − 1 , what is the half‑life of the reaction?

Half-life of the reaction is 0.072s.

Explanation:

In a first-order reaction, half-life, t1/2, is defined as:

(1)

Where k is the rate constant of the reaction.

In the problem, the thermally descomposition of cyclopropane has a rate constant of 9.6s⁻¹. Replacing in (1):

I hope it helps!

the answer is na (sodium)

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.