Sulfur and fluorine react in a combination reaction to produce sulfur hexafluoride: S (s) 3F 2(g) SF 6 (g) The maximum amount of SF 6 that can be produced from the reaction of 3.5 g of sulfur with of fluorine is g.

15.95 g

Explanation:

Calculation of the moles of sulfur as:-

Mass = 3.5 g

Molar mass of sulfur = 32.065 g/mol

The formula for the calculation of moles is shown below:

Thus,

From the reaction,

1 mole of sulfur on reaction forms 1 mole of sulfur hexafluoride

0.1092 mole of sulfur on reaction forms 0.1092 mole of sulfur hexafluoride

Molar mass of sulfur hexafluoride = 146.06 g/mol

Mass= Moles*Molar mass = 0.1092*146.06 g = 15.95 g

15.95 g is the maximum amount of that can be produced from the reaction of 3.5 g of sulfur with of fluorine.

am i too late?

explanation:

the answer is 303.15 or 303