When solid (NH4)(NH2CO2)(NH4)(NH2CO2) is introduced into and evacuated flask at 25∘C25∘C, the total pressure of gas at equilibrium is 0.30.3 atm. What is the value of Kpat25∘CKpat25∘C?

Kp = 0.004  = 4*10^-3

Explanation:

Step 1: Data given

Temperature = 25.0 °C

the total pressure of gas at equilibrium is 0.30 atm

Step 2: The balanced equation

NH4(NH2CO2)(s) ⇆ 2NH3(g) + CO2(g)

For 1 mol NH4(NH2CO2) we have 2 moles NH3 and 1 mol CO2

Step 3: The total pressure

Total pressure = pNH3 + pCO2

Total pressure = 2X + X

Total pressure = 3X = 0.30

X = 0.10

Step 4: The partial pressures

pNH3 = 2X = 2*0.10 = 0.20 atm

pCO2 = X = 0.10 atm

Step 5: Calculate Kp

Kp = (pNH3)²*(pCO2)

Kp = (0.20²)*0.10

Kp = 0.004  = 4*10^-3

1 a

2 d

3 a

4 c

explanation:

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.