Answers: 3
![K = \frac{[NOBr]^2}{[NO]^2[Br_2]}](/tpl/images/0534/2459/d157a.png)
(1)![1.3x10^{-2} = \frac{[NOBr]^2}{[0.89]^2[0.562]}](/tpl/images/0534/2459/0b578.png)
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What is the concentration of NOBr, if the concentration of NO was measured to be 0.89 M, Br2 was mea...
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