An x-ray beam with wavelength 0.170 nm is directed at a crystal. As the angle of incidence increases, you observe the first strong interference maximum at an angle 62.5 ∘. What is the spacing d between the planes of the crystal?

The spacing (d) between the planes of the crystal is 0.096nm.

BRAGG'S LAW EQUATION:

2dsinθ = nλ

Where;

d = nλ ÷ 2sinθ

According to this question;

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The distance between the scattering planes in the crystal is d = 0.95 A°

Explanation:

The Bragg's equation is given by

                                      2d sinθ = nλ

where,

d is the distance between the scattering planes in the crystal.

θ is the angle of diffraction.

n is the order of diffraction.

λ is the wavelength of X rays.

Given λ = 0.17 nm = 1.7 A°, angle = 62.5

                          2 d sin(62.5)    = 1 1.7 A°  

                                                    d = 0.95 A°  

The distance between the scattering planes in the crystal is d = 0.95 A°

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :