A rectangular block floats in pure water with 0.5 in, above the surface and 1.5 in below the surface. When placed in an aqueous solution, the block of material floats with 1 in. below the surface. Estimate the specific gravities of the block and the solution. (Suggestion: Call the horizontal cross-sectional area of the block A. A should cancel in your calculations.)

Explanation:

We will calculate the specific gravity of the block as follows.

    Specific gravity of block =

                   =

                   = 0.75

And, the specific gravity of the solution is as follows.

 Specific gravity of solution =

            =

            = 1.5

As the given block is rectangular, and its volume is directly proportional to its height and A is not needed in these calculations.

Also, we can note here that the term specific gravity is no longer approved and has been replaced by the term relative density.

58750.08068 is the answer i think