50g of zinc are reacted with 50g of hydrogen chloride. Calculate the amount of hydrogen made. Equation: Zn + _2_HCl --> ___ZnCl2 + ___H2

1.38 g H₂

Explanation:

Zn  +  2 HCl  ⇒  ZnCl₂  +  H₂

To solve, you need to first find the limiting reagent.  Convert grams to moles and use the mole ratios in the chemical equation to convert from the reagent to the product.  The reagent that produces the least is the limiting reagent.

Zn

(50 g)/(65.38 g/mol) = 0.7648 mol Zn

(0.7648 mol Zn) × (1 mol H₂/1 mol Zn) = 0.7648 mol H₂

HCl

(50 g)/(36.46 g/mol) = 1.371 mol HCl

(1.371 mol HCl) × (1 mol H₂/2 mol HCl) = 0.6857 mol H₂

HCl produces less product so this is the limiting reagent.  Since you have already converted to moles, you simply need to convert from moles to grams to find the amount of hydrogen made.

(0.6857 mol) × (2.016 g/mol) = 1.38 g H₂

You will have 1.38 g of H₂.

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