Calculate the volume in liters of a 0.0015/molL calcium sulfate solution that contains 25.0g of calcium sulfate CaSO4 . Be sure your answer has the correct number of significant digits.

The volume of a 0.0015 calcium sulfate solution that contains 25.0 g of calcium sulfate CaSO₄ is 122.53 liters.

Explanation:

Molarity (M) is the number of moles of solute that are dissolved in a given volume. Molarity is expressed by:

Molarity is expressed in units

In this case you have 25.0g of calcium sulfate CaSO₄. First of all you need to know the amount of moles that mass represents. For that you must first know the atomic masses of each element:

Then the molar mass of the compound calcium sulfate is:

molar mass= 40 g/mol + 32 g/mol + 4*16 g/mol= 136 g/mol

It is then possible to apply a rule of three as follows: if 136 g represents 1 mol of the compound calcium sulfate, 25 g how many moles are they?

moles≅0.1838

Now you can apply a rule of three knowing the molarity of 0.0015 : if 0.0015 moles represents 1 liter of solution, 0.1838 moles how many liters are they?

volume=122.53 liters

The volume of a 0.0015 calcium sulfate solution that contains 25.0 g of calcium sulfate CaSO₄ is 122.53 liters.

fe 55.85 g/mol and h2o 18.02 g/mol.