For the oxidation–reduction reaction equation 2 Rb + Br 2 ⟶ 2 RbBr 2Rb+Br2⟶2RbBr indicate how many electrons are transferred in the formation of one formula unit of product.

2e⁻ are transferred in the formation of one formula unit of product

Explanation:

The reaction is:

2Rb + Br₂ → 2RbBr

In ground state, both elements have 0 as oxidation state.

In the RbBr, Rb acts with+1 and Br with -1.

Rb increased the oxidation state → Oxidation

Br decreased the oxidation state → Reduction

Rb → Rb⁺ + 1e⁻

Br₂ + 2e⁻ → 2Br⁻

Bromine had to gained 2 electrons, to decreased the oxidation state, so

(Rb → Rb⁺ + 1e⁻ ) ₓ2 = 2Rb → 2Rb⁺ + 2e⁻

(Br₂ + 2e⁻ → 2Br⁻) ₓ1 =  Br₂ + 2e⁻ → 2Br⁻

2Rb + Br₂ + 2e⁻ → 2Br⁻ + 2Rb⁺ + 2e⁻

If we cancel the electrons, we reach the balanced reaction. In conclussion, 2 e⁻

< > according to newton's third law of motion, forces always act in equal but opposite pairs. another way of saying this is for every action, there is an equal but opposite reaction.< >

the answer is c.the valence of the atoms combine .