If 0.38 M of an aqueous solution of magnesium nitrate hexahydrate (Mg(NO3)2 ᐧ 6H2O) was prepared in the laboratory, how many mL of the solution would you need to obtain 4.871 grams of this solute?

50 mL

Explanation:

Given data

Molar concentration (M): 0.38 MMass of solute: 4.871 gMolar mass of the solute: 256.41 g/mol

We can find the required volume using the following expression.

M = mass of solute / molar mass of solute × liters of solution

liters of solution = mass of solute / molar mass of solute × M

liters of solution = 4.871 g / 256.41 g/mol × 0.38 mol/L

liters of solution = 0.050 L = 50 mL

Ibelieve it's temperature! i'm not 100% sure.

The answer to the question: choose the correct statement.  a) when ethane reacts with fluorine gas the product is less stable.b) addition reactions of unsaturated hydrocarbons and halogens requires a high activation energy.  c)the double covalent bond within unsaturated hydrocarbons requires a lot of energy to break.  d)the double covalent bond within unsaturated hydrocarbons can be broken easily.is: a) when ethane reacts with fluorine gas the product is less stable.