A chemistry student needs 60.0 ml of ethanolamine for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the student discovers that the density of ethanolamine is 1.02 g cm^-3. Calculate the mass of ethanolamine the student should weigh out. Round your answer to 3 significant digits.

* 10^

The student should weigh out 61.2g of ethanolamine [6.12 * 10]

Explanation:

In this question, we are expected to calculate the mass of ethanolamine needed to make 60.0ml of it given that the density of the ethanolamine in question is 1.02g/cm^3

Mathematically, it has been shown that mass = density * volume

Hence, by multiplying the density by the volume, we get the mass.

Now, from the question we can see that we have the values for the density and the volume. We now need to get the mass.

Since cm^3 is same as ml, we need not perform any conversion.

Hence, the needed mass is:

60 * 1.02 = 61.2g

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then the atmosphere can be freezing as the water vapor in the air is at maximum (100%) and can be severely cold

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