Calculate Kc for the reaction: 2 HI(g) ⇄ H2(g) + I2(g) given that the concentrations of each species at equilibrium are as follows: [HI] = 0.85 mol/L, [I2] = 0.60 mol/L, [H2] = 0.27 mol/L.

The value of for the given reaction is 0.224

Explanation:

For the given chemical equation:

The expression of for given equation follows:

We are given:

Putting values in above expression, we get:

Hence, the value of for the given reaction is 0.224