Chemistry, 02.03.2020 19:22, PONBallfordM89
A 11.6 g piece of metal is heated to 98°C and dropped into a calorimeter containing 50.0 g of water (specific heat capacity of water is 4.18 J/g°C) initially at 20.5°C. The empty calorimeter has a heat capacity of 125 J/K. The final temperature of the water is 28.2°C. Ignoring significant figures, calculate the specific heat of the metal.
Answers: 1
![q=-[q_1+q_2]](/tpl/images/0530/4537/f9283.png)
![m\times c\times (T_f-T_1)=-[c_1\times (T_f-T_2)+m_2\times c_2\times (T_f-T_2)]](/tpl/images/0530/4537/372b8.png)
= heat absorbed by the calorimeter
= heat absorbed by the water
= specific heat of calorimeter = 
= specific heat of water = 
= mass of water = 50.0 g
= final temperature = 
= temperature of metal = 
= temperature of water = 
![11.6g\times c\times (28.2-98)^oC=-[125J/^oC\times (28.2-20.5)^oC+50.0g\times 4.18J/g^oC\times (28.2-20.5)^oC]](/tpl/images/0530/4537/17b20.png)
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A 11.6 g piece of metal is heated to 98°C and dropped into a calorimeter containing 50.0 g of water...
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