How many molecules are there in 30.0 g of methane gas (CH4)?

a. 1.00 mole of molecules
b. 3.011 x 10^23 molecules
c. 1.13 x 10^24 molecules
d. 6.88 x 10^23 molecules
e. 30 molecules

We have 1.13 * 10^24 molecules in 30.0 grams CH4 (option C)

Explanation:

Step 1: Data given

Mass of CH4 = 30.0 grams

atomic mass C = 12.00 g/mol

atomic mass H = 1.01 g/mol

Step 2: Calculate molar mass CH4

Molar mass CH4 = 12 + 4*1.01 g/mol

Molar mass CH4 = 16.04 g/mol

Step 3: Calculate moles CH4

Moles CH4 = mass CH4 / molar mass CH4

Moles CH4 = 30.0 grams / 16.04 g/mol

Moles CH4 = 1.87 moles

Step 4: Calculate number of molecules

number of molecules =moles * number of Avogadro

number of molecules = 1.87 * 6.022 * 10^23 / moles

number of molecules = 1.13 * 10^24 molecules

We have 1.13 * 10^24 molecules in 30.0 grams CH4 (option C)

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."

the maximum mass of nh3 is nh3 in grams