10 points) Given the following two half-reactions, write the overall reaction in the direction in which it is product-favored, and calculate the standard cell potential. Pb2+ (aq) + 2 e–à Pb (s) Eº= –0.126 VFe3+ (aq) + e–à Fe2+ (s) Eº = +0.771 V

The over all reaction :

The standard cell potential of the reaction is 0,.897 Volts.

Explanation:

Reduction at cathode :

..[1]  

Reduction potential of  to

Oxidation at anode:

.[2]

Reduction potential of  to

To calculate the of the reaction, we use the equation:

Putting values in above equation, we get:

The over all reaction : 2 × [1] + [2]

The standard cell potential of the reaction is 0,.897 Volts.

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explanation:

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