Aqueous potassium phosphate reacts with aqueous aluminum chloride to form aqueous potassium chloride and solid aluminum phosphate. Write the balanced chemical equation for the reaction. Include physical states.

The balanced equation of the reaction between aqueous aluminum chloride and potassium phosphate to form aqueous potassium chloride and solid aluminum phosphate would be:

+   --->   +  

Aqueous potassium phosphate has the formula

Aqueous aluminum chloride has the formula

Aqueous potassium chloride has the formula

Solid aluminum phosphate has the formula

The balanced equation for the reaction can, thus, be written as:

  +   --->   +  

More on balancing chemical equations can be found here: link

Al^3+(aq) + PO4^3-(aq) → AlPO4(s)

Explanation:

Step 1: Data given

potassium phosphate = K3PO4

aluminum chloride = AlCl3

potassium chloride = KCl

aluminum phosphate = AlPO4

Step 2: The unbalanced equation

K3PO4(aq) + AlCl3(aq) → KCl (aq)+ AlPO4(s)

On the left side we have 3x K (in K3PO4), on the right side we have 1x K (in KCl). To balance the amount of K on both sides, we have to multiply KCl (on the right side ) by 3. Now the equation is balanced.

K3PO4(aq) + AlCl3(aq) → 3KCl(aq)+ AlPO4(s)

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will look like this

Al^3+(aq) + PO4^3-(aq) → AlPO4(s)

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation:

it's c. elements are placed in rows based on how may valencies electrons have.