An enzyme catalyzes a reaction with a K m of 6.50 mM and a V max of 4.25 mM ⋅ s − 1 . Calculate the reaction velocity, v 0 , for each substrate concentration.

The given question is incomplete. The complete question is as follows.

An enzyme catalyzes a reaction with a K m of 6.50 mM and a V max of 4.25 . Calculate the reaction velocity, v 0 , for each substrate concentration.

(a) 4.00 mM,       (b) 6.50 mM

Explanation:

It is given that the enzyme catalyzes a reaction with a of 6.50 mM and a of 4.25 .

So, we will calculate the reaction velocity (), for the following substrate concentrations as follows.  

                 V =

Putting the given values into the above formula as follows.

          V =

a) It is given that [S] = 4 mM

So,     V =

          V =

          V = 1.619 mM/s

Hence, the reaction velocity (), for substrate concentration 4 mM is 1.619 mM/s.

b)   It is given that [S] = 6.5 mM

So,       V =

            V =

            V = 2.125 mM/s

Hence, the reaction velocity (), for substrate concentration 6.5 mM is 1.619 mM/s.

tracks, burrows, eggshells, nests, tooth marks, or gastroliths