Assign oxidation numbers to each atom in the following compounds and ion: H2O2, ClO3−, H2SO4. You do not need to include a positive sign for a positive oxidation number.

Explanation:

Oxidation number is defined as the number holded by an atom by either gain or loss of electrons when it chemically combines with another atom.

Oxidation number of each atom in the given compounds is as follows.

(a)  

Oxidation number of hydrogen is +1 so, the oxidation number of oxygen in   is as follows.

               2(+1) + 2x = 0

                    x = -1

So, oxidation number of H is +1 and O is -1.

(b)  

Oxidation number of oxygen is -2. So, oxidation number of chlorine is calculated as follows.

          x + 3(-2) = -1

               x = +5

Hence, the oxidation number of Cl is +5 and O is -2.

(c)  

Oxidation number of hydrogen is +1 and oxygen is -2. Now, we will calculate the oxidation number of sulfur as follows.

           2(+1) + x + 4(-2) =0

             2 + x -8 = 0

                   x = +6

Hence, the oxidation number of H is +1, S is +6 and O is -2.

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oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).