Calculate the number of moles of sodium carbonate originally present, if 6.0 ml of 0.100 M HCl were used to titrate the mixture with phenolphthalein as the indicator. Show your calculations.

0.0006 mole

Explanation:

Considering:

Or,

Given :

For HCl :

Molarity = 0.100 M

Volume = 6.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 6.0×10⁻³ L

Thus, moles of potassium iodide :

Moles of HCl = 0.0006 moles

From the reaction shown below:-

1 mole of HCl reacts with 1 mole of sodium carbonate.

So,

0.0006 mole of HCl reacts with 0.0006 mole of sodium carbonate.

Moles of sodium carbonate = 0.0006 moles