Two solutions are created by mixing one solution containing lithium nitrate with one containing sodium phosphate.

a. Solution A is created by mixing 0.500 L of 0.30 M LiNO3 with 0.400 L of 0.20 M Na3PO4.
b. Solution B is created by mixing 0.400 L of 0.20 M LiNO3 with 0.500 L of 0.30 M Na3PO4.
c. In which of these solutions will lithium phosphate precipitate? Lithium phosphate has a Ksp = 2.3x10−4
d. Select the solution(s) that will form a precipitate.

Solution A

Explanation:

For this question we have to compare Qsp, the solubility product reaction quotient, with Ksp.

If Qsp > Ksp we know a precipitate of Li₃PO₄ will form.

Therefore, what we need to do is calculate the concentrations of Li⁺ and PO₄³⁻ from the data given.

Q which has the same form as Ksp

Q = [Li⁺]³ x [PO₄³⁻]

a. [Li⁺] = mol Li⁺ / Vol soln (L)

mol Li⁺ = 0.500 L x 0.30 mol/L = 0.15 mol

Vol solution = 0.500 L + 0.400 L = 0.900 L

[Li⁺] = 0.15 mol / 0.900 L = 0.167 M

mol PO₄³⁻ = 0.400 L x 0.20 mol/L = 0.08 mol

[PO₄³⁻] = 0.08 mol / 0.900 L = 0.089 M

Q = (0.167)³ x 0.089 = 4.1 x 10⁻⁴

Q > Ksp ( 4.1 x 10⁻⁴ > 2.3 x 10⁻⁴ )  will precipitate some Li₃PO₄

b. mol Li⁺ = 0.400 L x 0.20mol Li⁺/L = 0.08 mol

[Li⁺] = 0.08 mol / 0.9 L = 8.9 x 10⁻² M

mol PO₄³⁻ = 0.500 L x 0.30 mol/L = 0.15 mol

[PO₄³⁻] = 0.15 L / 0.9 L = 0.17 M

Q = (8.9 x 10⁻²)³ x 0.15 = 1.1 x 10⁻⁴

Q < Ksp it will not precipitate

answer: e.   sour taste

explanation: acids are those substances which dissociates in water to give ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. acids are sour in taste. example: hcl

bases are those substances which dissociates in water to give ions or accepts ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. bases are bitter in taste. bases are slippery in nature.