How many mL are 2.3 mol of CO2 at STP?

0.052mL

Explanation:

1mole of a gas occupy 22.4L.

Therefore, 1 mole of CO2 will also occupy 22.4L.

If 1mole of CO2 occupies 22.4L,

Then 2.3moles of CO2 will occupy = 2.3 x 22.4 = 51.52L

coverting this volume to mL, we simply divide by 1000 as shown below:

51.52/1000 = 0.05152mL = 0.052mL

The volume of 2.3 moles CO2 is 51.5 L = 51500 mL

Explanation:

Step 1: Data given

Number of moles CO2 = 2.3 moles

Step 2: Calculate volume CO2

p*V= n*R*T

⇒with p = the pressure = 1 atm

⇒with V = the volume = TO BE DETERMINED

⇒with n = the number of moles = 2.3 moles

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒with T = the temperature = 273 K

V = (nRT)/p

V = (2.3*0.08206*273)/1

V = 51.5 L

The volume of 2.3 moles CO2 is 51.5 L = 51500 mL

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm