Given the following unbalanced chemical equation, how many grams of K2O can be produced from 132 grams of potassium and excess oxygen gas?___K(s) + ___O2(g) Imported Asset ___K2O(s)

159.0 grams

318.0 grams

13.95 grams

2.962 x 10-1 grams

The answer to your question is 159.0 grams

Explanation:

data

mass of K₂O = ?

mass of K = 132 g

Process

1.- Balance the chemical reaction

Chemical reaction

                   K(s)  +  O₂  ⇒   K₂O

             Reactants   Elements   Products

                    1                  K                 2

                    2                 O                 1

This reaction is unbalanced

                    4K(s)  +  O₂  ⇒   2K₂O

             Reactants   Elements   Products

                    4                  K                 4

                    2                 O                 2

Now the reaction is balanced

2.- Calculate the mass of K₂O

Atomic mass of K = 39 x 4 = 156 g

Molar mass of K₂O = 2[(39 x 2) + 16] = 188 g

                  156 g of K 188 g of K₂O

                  132 g of K    x

                  x = (132 x 188) / 156

                 x = 159.0 grams

159 grams of K2O can be produced

Explanation:

Step 1: Data given

Mass of potassium = 132 grams

Molar mass of potassium = 39.10 g/mol

Step 2: The balanced equation

4K(s) + O2(g) → 2K2O(s)

Step 3: Calculate moles K

Moles K = mass K / molar mass K

Moles K = 132.0 grams / 39.10 g/mol

Moles K = 3.376 moles

Step 4: Calculate moles K2O

For 4moles K we need 1 mol O2 to produce 2 moles K2O

For 3.376 moles K we'll have 3.376/2 = 1.688 moles K2O

Step 5: Calculate mass K2O

Mass K2O = moles K2O * molar mass K2O

Mass K2O = 1.688 moles * 94.2 g/mol

Mass K2O = 159 grams

159 grams of K2O can be produced

43.452

step-by-step explanation:

284 times .153 = 43.452