Consider the following intermediate chemical equations. 2 equations. First: C(s)+(1/2)O2(g) >CO(g). Second: CO(g)+(1/2)O2(g) >CO2(g). How will oxygen appear in the final chemical equation?

The oxygen will appear in the final stage if the oxygen is excess from the beginning.

Explanation:

1. C +(1/2)O2 —> CO

2. CO+(1/2)O2—> CO2

The first stage explains that the oxygen is limited and hence CO is produced.

The 2nd stage explains that if the oxygen is excess, then CO2 will be produced.

The overall reaction when oxygen is excess is given by:

C + O2 —> CO2

the answer is d. 74.02