For the neutralization reaction: 2 HCl + Ca(OH)2 -> CaCl2 + 2H20, how many
grams of Ca(OH)2 are required to produce 135 grams CaCl2? The reaction
occurs in the presence of excess HCL.
60.29
9049
1359
180 g
Submit
Law of Conservation of Matter

90g of Ca(OH)2

Explanation:

2HCl + Ca(OH)2 —> CaCl2 + 2H20

Molar Mass of Ca(OH)2 = 40 + 2( 16 + 1) = 40 + 2(17) = 40 + 34 = 74g/mol

Molar Mass of CaCl2 = 40 + (2 x 3.5) = 40 + 71 = 111g/mol

From the equation,

74g of Ca(OH)2 produced 111g of CaCl2.

Therefore, Xg of Ca(OH)2 will produce 135g of CaCl2 i.e

Xg of Ca(OH)2 = (74 x 135) / 111 = 90g.

Therefore, 90g of Ca(OH)2 are required to produce 135g of CaCl2

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."

the answer to this question is 3.