A silver wire and an aluminum wire of the same length have the same resistance. What is the ratio of the diameter of the silver wire to that of the aluminum wire.

The ratio of the diameter of the silver wire to that of the aluminum wire is 0.751

Explanation:

The resistivity of silver wire is 1.59×10^-8 ohm-meter. Let its diameter be Ds. Area = πDs^2/4

The resistivity of aluminum wire is 2.82×10^-8 ohm-meter. Let its diameter be Da. Area = πDa^2/4

Resistance and length of both wires are the same

Resistance/length = resistivity/area

1.59×10^-8/πDs^2/4 = 2.82×10^-8/πDd^2/4

(Ds/dD)^2 = 0.564

(Ds/Dd) = √0.564 = 0.751

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8