A solution was prepared by mixing 40.00 mL of 0.100 M HNO3 and 180.00 mL of 0.200 M HNO3 . Calculate the molarity of the final solution of nitric acid. Assume that the volumes are additive

The concentration of in the final solution is 0.182 M

Explanation:

To calculate the molarity of the solution after mixing 2 solutions, we use the equation:

where,

are the n-factor, molarity and volume of the

are the n-factor, molarity and volume of the

We are given:

Putting all the values in above equation, we get:

Hence, the concentration of in the final solution is 0.182 M

8

explanation:

each principal energy level above the first contains one s orbital and three p orbitals. a set of three p orbitals, called the p sublevel, can hold a maximum of six electrons. therefore, the second level can contain a maximum of eight electrons - that is, two in the s orbital and 6 in the three p orbitals.

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