What is the empirical formula of a substance that contains 2.64 g of c

Explanation:

What is the empirical formula of a substance that contains 2.64 g of C, 0.444 g of H, and 7.04 g of O?

First, find the number of mole of each element:

moles = mass/molar mass.

moles C = 2.64 g / 12.011 = 0.220

moles H = 0.444 g/ 1.008 = 0.440

moles = 7.04 g / 15.999 = 0.440

Divide each mole by the smallest mole

C = 0.220/0.220 = 1

H = 0.440/0.220 = 2

O = 0.440/0.220 = 2

Hence, the empirical formular is

if two electrons have the same n, the same ℓ, and the same ml, then they are in the same orbital. the pauli exclusion principle states that no two identical fermions (a fancy word for electrons and other subatomic particles like electrons) may occupy the same quantum state in an atom simultaneously.