A concentration cell consists of two Sn/Sn2+ half-cells. The cell has a potential of 0.10 V at 25 ºC. What is the ratio of the Sn2+ concentrations in the two half-cells?

The ratio of  in the cell is

Explanation:

The half reactions for the cell is:  

Oxidation half reaction (anode):  

Reduction half reaction (cathode):  

In this case, the cathode and anode both are same. So, will be equal to zero.

To calculate cell potential of the cell, we use the equation given by Nernst, which is:

where,

n = number of electrons in oxidation-reduction reaction = 2

= 0.10 V

 = ?

Putting values in above equation, we get:

Hence, the ratio of  in the cell is

it would be a gas formation

answer: semi-infinite solid initially at a uniform temperature of 400 ◦c is cooled at its surface by convection. the cooling fluid at a constant temperature of 200 ◦c has a convective coefficient (ha) of 250 w/m2.k. the physical properties of the solid: k = 20 w/m.k and α = 4 * 10-5  m2/s. using δx = 0.04 m and δt = 10 s. write the finite difference equations describing the transient heat transfer of the first five δx and the temperature profile after 30 s.