Consider the following equilibrium. 2 SO2 (g) + O2 (g) 2 SO3 (g) The equilibrium cannot be established when is/are placed in a 1.0-L container.

Question is incomplete, the complete question is pasted below.

Consider the following equilibrium. 2SO2(g) + O2(g) ⇌2SO3(g) The equilibrium cannot be established when is/are placed in a 1.0-L container?

A) 0.50 mol O2 (g) and 0.50 mol SO3 (g)

B) 1.0 mol SO3 (g)

C) 0.25 mol SO2 (g) and 0.25 mol O2 (g)

D) 0.75 mol SO2 (g)

E) 0.25 mol of SO2 (g) and 0.25 mol of SO3 (g)

The correct answer is : D) 0.75 mol SO2 (g)

Explanation:

Option A is not true because both SO3 can be converted into SO2 and O2 and equilibrium can be achieved.

Option B is not true because SO3 will be decomposed into SO2 and O2 and can achieve equilibrium.

Option C is not true because both SO2 and O2 will react and make SO3 and can achieve equilibrium.

Option D is correct because SO2 requires O2 to react and form SO3. Since O2 is not present, thus reaction will not occur and equilibrium will not be achieved.

Option E is not true because SO3 can decompose into O2 and SO2 and can achieve equilibrium.

a 20-cm-long, cylindrical graphite (pure carbon) rod is inserted into an oxidizing atmosphere at 1145 k and 1.013 x 105 pa pressure. the oxidizing process is limited by the diffu- sion of oxygen counterflow to the carbon monoxide that is formed on the cylindrical surface.

um i think it might be a car?