Liquid hexane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water . If of carbon dioxide is produced from the reaction of of hexane and of oxygen gas, calculate the percent yield of carbon dioxide. Be sure your answer has the correct number of significant digits in it.

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Liquid hexane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water. If 9.90 g of carbon dioxide is produced from the reaction of 4.31 g of hexane and 26.9 g of oxygen gas, calculate the percent yield of carbon dioxide. Be sure your answer has the correct number of significant digits in it.

The percent yield of carbon dioxide is 75.0 %

Explanation:

To calculate the number of moles, we use the equation:

    .....(1)

Given mass of hexane = 4.31 g

Molar mass of hexane = 86.2 g/mol

Putting values in equation 1, we get:

Given mass of oxygen gas = 26.9 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

The chemical equation for the combustion of hexane follows:

By Stoichiometry of the reaction:

2 moles of hexane reacts with 19 moles of oxygen gas

So, 0.05 moles of hexane will react with =  of oxygen gas

As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, hexane is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of hexane produces 12 moles of carbon dioxide gas

So, 0.05 moles of hexane will produce = of carbon dioxide gas  

Now, calculating the mass of carbon dioxide from equation 1, we get:

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide = 0.3 moles

Putting values in equation 1, we get:

Experimental yield of carbon dioxide = 9.90 g

Theoretical yield of carbon dioxide = 13.2 g

Putting values in above equation, we get:

Hence, the percent yield of the carbon dioxide is 75.0 %.

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