Balance the chemical equation given below, and determine the number of grams of MgO are needed to produce 15.0 g of Fe2O3. MgO(s) + Fe(s) → Fe2O3(s) + Mg(s)

Balanced reaction:

3MgO + 2Fe -> 3Mg + Fe2O3

11.3 g of MgO are needed to produce 15 g of Fe2O3

Explanation:

The balanced reaction is:

3MgO + 2Fe -> 3Mg + Fe2O3

Ratio is 1:3. First of all we determine the moles of produced oxide.

15 g . 1mol / 159.7 g = 0.0939 moles.

Now, the rule of three:

1 mol of oxide was produced by 3 moles of MgO

Then, 0.0939 moles of oxide were produced by 0.282 moles.

If we convert the moles to mass, we will get the answer 0.282 mol . 40.3g / 1mol = 11.3 g

We need 11.35 grams of MgO

Explanation:

Step 1: Data given

Mass of Fe2O3 = 15.0 grams

Molar mass Fe2O3 = 159.69 g/mol

Step 2: The balanced equation

3MgO(s) +  2Fe(s) →  Fe2O3(s) + 3Mg(s)

Step 3: Calculate moles Fe2O3

Moles Fe2O3 = mass Fe2O3 / molar mass Fe2O3

Moles Fe2O3 = 15.0 grams / 159.69 g/mol

Moles Fe2O3 = 0.0939 moles

Step 4: Calculate moles MgO

For 3 moles MgO we need 2 moles Fe to produce 1 mol Fe2O3 and 3 moles Mg

For 0.0939 moles Fe2O3 we need 3* 0.0939 = 0.2817 moles MgO

Step 5: Calculate mass MgO

Mass MgO = moles MgO * molar mass MgO

Mass MgO = 0.2817 moles * 40.30 g/mol

Mass MgO = 11.35 grams

We need 11.35 grams of MgO

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bases are those substances which dissociates in water to give ions or accepts ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. bases are bitter in taste. bases are slippery in nature.

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