8. Calculate the percentage composition of sodium nitrate, NaNO3.

The percent composition in sodium nitrate has been 27.05% Na, 16.47% N, and 56.47% Oxygen.

Sodium nitrate has is the molecular compound that has been consisted of sodium, nitrogen, and oxygen.

1 mole of sodium nitrate has consisted of 1 sodium atom, 1 nitrogen, and 3 oxygen atoms.

The molecular mass of sodium nitrate has been:

= Mass of Na + Mass of N + Mass of O.

Molecular mass of = 23 + 14 + (16 × 3) g/mol

Molecular mass of = 85 g/mol.

The percent composition has been :

Percent composition =

Percent composition of sodium = 27.05 %

Percent composition of nitrogen = 16.47 %.

Percent composition of Oxygen = 56.47%.

The percent composition in sodium nitrate has been 27.05% Na, 16.47% N, and 56.47% Oxygen.

For more information about percent composition, refer to the link:

link

27.06%

Explanation:

First let us calculate the molar mass of NaNO3. This is illustrated below:

MM of NaNO3 = 23 + 14 + (16x3) = 23 + 14 + 48 = 85g/mol

Now, we see that NaNO3 contains 1atom of Na.

Therefore the percentage composition of Na in NaNO3 is given by:

(23/85) x 100 = 27.06%

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