Chemistry, 24.02.2020 17:26, brookemcelhaney
If a temperature increase from 18.0 ∘C to 37.0 ∘C triples the rate constant for a reaction, what is the value of the activation barrier for the reaction?
Answers: 1
![\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]](/tpl/images/0521/2442/6d953.png)
= rate constant at 
= rate constant at 
= 
= activation energy for the reaction = ?
= initial temperature = 
= final temperature = 
![\log (\frac{3K_1}{K_1})=\frac{Ea}{2.303\times 8.314J/mole.K}[\frac{1}{291K}-\frac{1}{310K}]](/tpl/images/0521/2442/bca6a.png)
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If a temperature increase from 18.0 ∘C to 37.0 ∘C triples the rate constant for a reaction, what is...
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