Given that K w Kw for water is 2.4 × 10 − 14 2.4×10−14 at 37 ∘ C, 37 ∘C, calculate the pH of a neutral aqueous solution at 37 ∘ C, 37 ∘C, which is the normal human body temperature.

The pH of the solution is 6.81

Explanation:

The chemical equation for the ionization of water follows:

The expression of for above equation, we get:

We are given:

Putting values in above equation, we get:

We are given:

Putting values in above equation, we get:

Hence, the pH of the solution is 6.81