Which of the following weak interactions would require the least amount of energy to disrupt? Group of answer choices
hydrogen bonds
ionic bonds
van der Walas interactions
disulfide bonds

Van der waals force

Explanation:

Van der waals force is the weakest and would require less energy to disperse. It’s also known as London forces and mostly found with the halogen groups which undergoes sublimation( solid-gas) change. This force is responsible for this feature.They are usually easily dispersed hence it can also be called dispersion forces

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j