Consider the first-order reaction described by the equation Cyclopropane gas isomerizes to propene gas. At a certain temperature, the rate constant for this reaction is 5.05 × 10 − 4 s − 1 . Calculate the half-life of cyclopropane at this temperature. t 1 / 2 = s Given an initial cyclopropane concentration of 0.00670 M , calculate the concentration of cyclopropane that remains after 2.00 hours. concentration.

The half-life would be 1372 seconds.

The concentration remains after 2 hours is 0.000177 M.

Explanation:

Given the initial concentration of was .

And the rate constant is

We need to calculate the half-life and the concentration remains after 2 hours.

First, we will use the formula of half-life of the first order reaction.

So, half-life would be 1372 seconds.

Now, we will find its concentration after 2 hours. That means

Use the equation

So, the concentration remains after 2 hours is 0.000177 M.

- calcium has greater affinity to bond with electron receptors than hydrogen does and hence, it has the ability to replace hydrogen in most of its compounds.

- lithium has 2 valence electrons in the product because it can make only 1 bond with hydrogen. beryllium has 4 valence electrons in the product because it can only make 2 bonds. it has fewer electrons than neon and can react with electron donors. each hydrogen has 2 valence electrons, the same as helium.

- the covalent bond formed between carbon and hydrogen is polar because carbon is more electronegative than hydrogen and it attracts the bonded electron pair closer to itself, thus giving hydrogen a partial positive charge.

- a hydrogen bond is a relatively weak bond that hydrogen atoms make with the electronegative atoms nitrogen, oxygen or fluorine.

so the best choice is a.) 2 calcium (ca) atoms

i'm pretty sure it is letter c.) car