Given the chemical equation: Fe2O3 + 3CO --> 2Fe + 3CO2
You need to make 112 g of iron (Fe). You have as much carbon monoxide (CO) as needed. How much iron oxide (Fe2O3) do you need to start with?

Question 3 options:

1 mole Fe2O3

2 moles Fe2O3

4 moles Fe2O3

56 moles Fe2O3

The answer to your question is 1 mol of Fe₂O₃

Explanation:

Data

mass of Fe = 112 g

mass of Fe₂O₃ = ?

Balanced chemical reaction

                 Fe₂O₃  +  3CO  ⇒  2Fe  + 3CO₂

Process

1.- Calculate the molar mass of Fe₂O₃ and 2Fe

molar mass Fe₂O₃ = (56 x 2) + (16 x 3) = 160 g

molar mass of Fe = 56 x 2 = 112 g

2.- Use proportions to calculate the mass of Fe₂O₃ formed

                    160 g of Fe₂O₃ 112 g of Fe

                      x                       112 g of Fe

                      x = (112 x 160)/112

                      x = 160 g of Fe₂O₃

3.- Calculate the moles of Fe₂O₃

                      160 g of Fe₂O₃ 1 mol

                      160 g of Fe₂O₃  x

                       x = (160 x 1)/160

                       x = 1 mol of Fe₂O₃