When the following equation is balanced using the smallest possible integers, what is the exponent of H2O in the reaction quotient expression? Al(s) + NaOH(aq) + H2O(l) <=> Na)Al(OH)4)(aq) + H2(g)

6

Explanation:

Al(s) + NaOH(aq) + H2O(l) <=> Na)Al(OH)4)(aq) + H2(g)

The balanced chemical equation is given as;

2 Al(s) + 2 NaOH(aq) + 6 H2O(l) = 2 Na(Al(OH)4)(aq) + 3 H2(g)

The exponent of H2O in the reaction quotient expression = 6

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%