Chemistry, 21.02.2020 18:47, miles45

The reaction of UO2+ with hydrogen ion in aqueous solution 2 UO2+ + 4 H+U4+ + UO22+ + 2 H2O is second order in UO2+ and third order overall. Complete the rate law for this reaction in the box below. Use the form k[A]m[B]n... , where '1' is understood for m, n ... (don't enter 1) and concentrations taken to the zero power do not appear. Rate =

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answered: kaylacornish06

Rate law of reaction : $R=k[UO_2^{+}]^2[H^+]^1$

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Order of the reaction = Sum of stoichiometrix coefficients coming in rate law of reaction.

$2 UO_2^{+} + 4 H^+\rightarrow U^{4+} + UO_2^{2+} + 2 H_2O$

Overall order of the reaction is = 3

Order of the recation with respect to $UO_2^{+}=2$

Rate law of reaction can be written as :

$R=k[UO_2^{+}]^2[H^+]^x$

3 = 2 + x

x = 3 - 2 = 1

Rate law of reaction : $R=k[UO_2^{+}]^2[H^+]^1$

answered: Guest

Answer: abeexplanation:

1. the question asks the most appropriate, which seems to rule out "all of the above." your choice appears to be the correct one.

2. the protocol described is good for identifying correlation, but not cause and effect. for cause/effect, you need to devise a protocol that will assign the treatment (or not) to groups that have essentially the same "demographics" with respect to all the other variables. your choice regarding control group seems appropriate. random assignment of treatment (choice d) may be appropriate also. (i think you can argue that b and d are just different descriptions of the same method.)

3. d will randomize the birds, but may not guarantee there are 10 in each group. e will do both, so seems the better choice.

comment on question 2

based on the problem statement, it seems clear that confident, attentive drivers are more likely to use daytime running lights. so, the protocol might need to be devised in such a way that the lights would be turned on or off without the driver's knowledge. (an attentive driver will figure it out.) assigning a confident, attentive driver to a group required to drive without running lights might mess with his/her confidence and attentiveness. you don't want your experiment to do that. (nor do you want the experiment to subject a driver to greater risk of accident as a consequence of driving without running lights.) experiments involving human safety are always problematic.

answered: Guest

4- c, because all matter stays the same no matter what. it is still there. 5- b, because matter is known as mass. 6-c because, flammability is a chemical property. malleability is changing the shape of an object.

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The reaction of UO2+ with hydrogen ion in aqueous solution 2 UO2+ + 4 H+U4+ + UO22+ + 2 H2O is secon...