Chemistry, 21.02.2020 03:56, reticentrobbie
Calculate the pH of a 0.078 M solution of NaOCl (Ka of HClO = 3.5 x 10-8). Enter pH to 3 decimal places.
Answers: 3
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![K_a = \frac{[CLO^-].[H_3O^+]}{[HCLO]} \\\\3.5X10^{-8} = \frac{[x].[x]}{[0.078-x]} \\\\3.5X10^{-8} =\frac{x^2}{0.078-x} \\\\x^2 = 3.5X10^{-8} (0.078-x)\\\\x^2 = 2.73X10^{-9} - (3.5X10^{-8})x\\\\x^2 + (3.5X10^{-8})x - 2.73X10^{-9} =0](/tpl/images/0518/7894/66965.png)
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Calculate the pH of a 0.078 M solution of NaOCl (Ka of HClO = 3.5 x 10-8). Enter pH to 3 decimal pla...
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