For an enzymatically catalyzed reaction in which the measured values for KM and Vmax are, respectively, 10.0 mM and 0.172 mM min-1, what is the value of the turnover number? The concentration of enzyme used in the reaction is 10.0 μM.

17.2 minutes is the value of the turnover number.

Explanation:

Using Michaelis-Menten equation:

Where  :

= max rate velocity

[S] = substrate concentration

= Michaelis-Menten constant

V = reaction rate

= catalytic rate constant

= initial enzyme concentration

We have :

is the rate is obtained when all enzyme is bonded to the substrate. is termed as the turnover number.

17.2 minutes is the value of the turnover number.

c. because step up transformer steps up the input voltage i.e increases the input voltage  

the number of turns are greater on the secondary side of step up transformer  

transformer does not handle dc current