Chemistry, 21.02.2020 00:00, ylianafghgfdsnm1479
The iodide ion reacts with hypochlorite ion (the active ingredient in chlorine bleaches) in the following way:
OCl−+I−→OI−+Cl−.
This rapid reaction gives the following rate data:
[OCl−](M) [I]−(M) Rate (M/s)
1.5×10^−3 1.5×10^−3 1.36×10^−4
3.0×10^−3 1.5×10^−3 2.72×10^−4
1.5×10^−3 3.0×10^−3 2.72×10^−4
a. Write the rate law for this reaction.
b. Calculate the rate constant with proper units.
c. Calculate the rate when [OCl-]= 1.8×10^3 M and [I-]= 6.0×10^4 M .
Answers: 3
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The iodide ion reacts with hypochlorite ion (the active ingredient in chlorine bleaches) in the foll...
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