Distilled vinegar contains a solution of acetic acid (CH3CO2H) in H2O. What is the concentration of the solution that results from diluting 500 ml of 0.839 M vinegar solution to 2.5 L?

0.168M

Explanation:

We obtained the following information from the question:

C1 = 0.839 M

V1 = 500mL = 500/1000 = 0.5L

C2 =?

V2 = 2.5L

Using the dilution formula, we can obtain the concentration of the diluted solution as follows:

C1V1 = C2V2

0.839 x 0.5 = C2 x 2.5

Divide both side by 2.5

C2 = (0.839 x 0.5) /2.5

C2 = 0.168M the concentration of the diluted solution is 0.168M

i think it is true since you can test the answer and can use observations to complete it.

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.