Write a balanced chemical equation for the reaction of aqueous potassium hydroxide with aqueous iron(III) chloride to form solid iron(III) hydroxide and aqueous potassium chloride. Express your answer as a chemical equation including phases.

The answer to your question is

             3KOH (aq)  +  FeCl₃(aq)   ⇒    Fe(OH)₃ (s)  +   3KCl (aq)

Explanation:

Data

Potassium hydroxide = KOH

Iron (III) chloride = FeCl₃

Iron (III) hydroxide = Fe(OH)₃

Potassium chloride = KCl

- Write the chemical equation

               KOH (aq)  +  FeCl₃(aq)   ⇒    Fe(OH)₃ (s)  +   KCl (aq)

                  Reactants              Elements        Products

                        1                             K                       1

                        1                             Fe                     1

                        3                            Cl                      1

                        1                              H                      3

                        1                              O                      3

This reaction is unbalanced

- Balancing the reaction

              3KOH (aq)  +  FeCl₃(aq)   ⇒    Fe(OH)₃ (s)  +   3KCl (aq)

                  Reactants              Elements        Products

                        3                             K                      3

                        1                             Fe                     1

                        3                            Cl                      3

                        3                              H                      3

                        3                              O                      3

This reaction is now balanced

b) mutualism

hope this : )

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j