What is the atom inventory for the following equation after it is properly balanced? NaOH + CuCl2 Imported Asset NaCl + Cu(OH)2 Reactants: Na = 1, O = 1, H = 1, Cu = 2, Cl = 2; Products: Na = 1, O = 1, H = 1, Cu = 2, Cl = 2 Reactants: Na = 1, O = 2, H = 2, Cu= 2, Cl= 2; Products: Na = 1, Cl = 1, Cu = 2, O = 2, H = 2 Reactants: Na = 1, O = 1, H = 1, Cu = 1, Cl = 21; Products: Na = 1, O = 1, H = 1, Cu = 1, Cl = 2 Reactants: Na = 2, O = 2, H = 2, Cu = 1, Cl = 2; Products: Na = 2, Cl = 2, Cu = 1, O = 2, H = 2

Reactants: Na = 2, O = 2, H = 2, Cu = 1, Cl = 2;

Products: Na = 2, Cl = 2, Cu = 1, O = 2, H = 2

Explanation:

NaOH + CuCL2 —> NaCl + Cu(OH)2

The balanced equation can be achieved by doing the following:

There are 2 oxygen and 2 hydrogen atom on the right side. This is balanced by putting 2 in front of NaOH as shown below:

2NaOH + CuCL2 —> NaCl + Cu(OH)2

This makes Na to be unbalanced. Now to balance Na, put 2 in front of NaCl as illustrated below

2NaOH + CuCL2 —> 2NaCl + Cu(OH)2

Now the equation is balanced.

Reactants: Na = 2, O = 2, H = 2, Cu = 1, Cl = 2

Products: Na = 2, Cl = 2, Cu = 1, O = 2, H = 2

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c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.