Chemistry, 19.02.2020 21:00, zitterkoph

A 150 g sample of a compound is comprised of 44% C, 9% H and the remainder is O by mass. What is the compound's empirical formula?

Answers: 1

Show answers

Answers

answered: ssargeant2559

The empirical formula for the given compound is CH_3O

Explanation:

We are given:

Percentage of C = 44 % of 150 g

Percentage of H = 9 % of 150 g

Percentage of O = 47 % of 150 g

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 66 g

Mass of H = 13.5 g

Mass of O = 70.5 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{66g}{12g/mole}=5.5moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{13.5g}{1g/mole}=13.5moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{70.5g}{16g/mole}=4.41moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 4.41moles.

For Carbon = $\frac{5.5}{4.41}=1.25\approx 1$

For Hydrogen = $\frac{13.5}{4.41}=3.06\approx 3$

For Oxygen = $\frac{4.41}{4.41}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1 : 3 : 1

Hence, the empirical formula for the given compound is CH_3O

answered: 501jmw

The empirical formula of the compound has been $\rm \bold{CH_3O}$ .

The empirical formula has been a whole unit formula with the application for the determination of the compound in the ratio of the constituent elements.

The empirical formula has been given by the computation of the moles of elements with respect to another.

Computation for Empirical formula:

The mass of elements in the compound has been calculated as x% of 150 g.

The mass of Carbon has been:

$\rm Mass\;C=\dfrac{44}{100}\;\times\;150\\Mass\;C=66\;g$

The mass of carbon has been 66 grams.

The mass of Hydrogen has been:

$\rm Mass\;H=\dfrac{9}{100}\;\times\;150\\Mass\;H=13.5\;g$

The mass of Hydrogen has been 13.5 grams.

The mass of Oxygen has been:

$\rm Mass\;O=\dfrac{47}{100}\;\times\;150\\Mass\;O=70.5\;g$

The mass of Oxygen has been 70.5 grams.

The moles of an element has been given by:

$\rm Moles=\dfrac{Mass}{Molar\;mass}$

The moles of following elements in the compound has been:

$\rm Moles\;C=\dfrac{66}{12} \\Moles\;C=5.5\;mol$

The moles of carbon in the compound has been 5.5 mol.

$\rm Moles\;H=\dfrac{13.5}{1} \\Moles\;H=13.5\;mol$

The moles of hydrogen in the compound has been 13.5 mol.

$\rm Moles\;O=\dfrac{70.5}{16} \\Moles\;O=4.41\;mol$

The moles of oxygen in the compound has been 4.41 mol.

The empirical formula for the compound has been given as the ratio of C : H : O.

C : H : O = 1 : 3 : 1

Thus, the empirical formula of the compound has been $\rm \bold{CH_3O}$ .

For more information about empirical formula, refer to the link:

answered: Guest

ugh fiel iente of insistí is did kiwis jaj

answered: Guest

the answer is true. hope it .

Other questions on the subject: Chemistry

Chemistry, 22.06.2019 01:30, josephaciaful

Follow the steps provided in the simulation to add water to the graduated cylinder, select one of the three samples (copper, silver, or gold), set its mass to the values given in the statements below, and calculate its density. here is a summary of the steps required: add water by clicking and holding prepare a known volume of water button. until the desired volume of water has been added. if more than the desired volume is added, click the reset button. button and redo the procedure. a single click will add about 21.0 ml of water. to set the mass, click and hold weigh out metal button. until the desired amount of metal is added to the weighing pan. once the desired mass of the metal is added, release the button. transfer the metal to water and then click on calculate density button. to see how the density is calculated using water displacement to measure the volume of the solid. to save time you can approximate the initial volume of water to â±1 ml and the initial mass of the solid to â±1 g. for example, if you are asked to add 23 ml of water, add between 22 ml and 24 ml. which metals in each of the following sets will have equal density? check all that apply.

Answers: 1

continue

Chemistry, 22.06.2019 06:00, mbrisen7420

Compare and contrast physical changes with chemical changes.

Answers: 3

continue

Chemistry, 22.06.2019 06:00, ehhshsh

Calculate the mass of silver needed to react with chlorine to produce 126g if silver chloride?

Answers: 3

continue

Chemistry, 22.06.2019 08:00, flakko1899

An electron moved from shell n = 2 to shell n = 1. what most likely happened during the transition? a fraction of a photon was added. a photon of energy was absorbed. a fraction of a photon was removed. a photon of energy was released.

Answers: 1

continue

Do you know the correct answer?

A 150 g sample of a compound is comprised of 44% C, 9% H and the remainder is O by mass. What is the...